Quants probability

[mkrazor]

im struggerling to find out how to work out this problem.

A sample of size n=49 is taken from the population having mean u=100 and the standard deviation o=12. find the probability that X will lie between 96 and 104?

I know the answer is 0.9802 but i dont know how they got that and just looking for some advice on how they worked it out.

 

[tiger]

p(96<X<104) = p((96-100)/(12/7)<Z<(104-100)/(12/7)) = 0.9802

 

[markhobbus]

don't you have to know what kind of distribution it is?

 

[tiger]

don't you have to know what kind of distribution it is?

u don't know central limit theorem?

 

[liber]

X is the the mean, not a single observation